| Re: echo other way to output a constant? [message #169484 is a reply to message #169476] |
Wed, 15 September 2010 01:45   |
rf
Messages: 19
Registered: September 2010
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Junior Member |
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"MikeB" <mpbrede(at)gmail(dot)com> wrote in message
news:4c8ff366(at)news(dot)x-privat(dot)org...
> Say I have the following code:
>
> <?php
>
>
> define('MAX_FILE_SIZE', 300);
>
> echo <<<_END
> <html><head><title>PHP Form Upload</title></head><body>
> <form method='post' action='UploadFile2.php'
> enctype='multipart/form-data'>
> <!-- MAX_FILE_SIZE must precede the file input field -->
> <input type="hidden" name="MAX_FILE_SIZE" value="" />
> Select a JPG, GIF, PNG or TIF File:
> <input type='file' name='filename' size='60' />
> <br/><input type='submit' value='Upload' /></form>
> _END;
>
> echo "</body></html>";
> ?>
>
> How can I get PHP to place the value of the constant MAX_FILE_SIZE in the
> value attribute for the hidden field MAX_FILE_SIZE?
>
> Since it does not start with a $-sign it is not interpreted as a variable.
> I tried putting it in curly braces {}, which sometimes work, but that
> didn't do the trick either.
All of this is mentioned in the manual.
echo <<<_END
<html><head><title>PHP Form Upload</title></head><body>
<form method='post' action='UploadFile2.php' enctype='multipart/form-data'>
<!-- MAX_FILE_SIZE must precede the file input field -->
<input type="hidden" name="MAX_FILE_SIZE" value="
_END;
echo MAX_FILE_SIZE;
echo <<<_END
" />
Select a JPG, GIF, PNG or TIF File:
<input type='file' name='filename' size='60' />
<br/><input type='submit' value='Upload' /></form>
_END;
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