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Re: why does in_array return true [message #169882 is a reply to message #169869]

Wed, 29 September 2010 10:23

Geoff Berrow
Messages: 16
Registered: September 2010

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Junior Member

On Tue, 28 Sep 2010 18:24:58 -0700 (PDT), heartmeat
<brendon(at)actrix(dot)co(dot)nz> wrote:

> I must be missing something obvious, but, given:
>
> var $haystack = array(0);
> var $needle = '0_50';

var is not used in PHP. Some confusion with JavaScript?

Are you perhaps expecting array(0) to give you and empty array? It
doesn't, it gives you an array with one element.

An empty array would be:
$haystack = array();

>
> why does:
>
> in_array($needle,$haystack) return true?

See other answers.
--
Geoff Berrow (Put thecat out to email)
It's only Usenet, no one dies.
My opinions, not the committee's, mine.
Simple RFDs www.4theweb.co.uk/rfdmaker

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[Message index]

		why does in_array return true By: heartmeat on Wed, 29 September 2010 01:24
		Re: why does in_array return true By: rf on Wed, 29 September 2010 01:47
		Re: why does in_array return true By: Denis McMahon on Wed, 29 September 2010 01:56
		Re: why does in_array return true By: Jerry Stuckle on Wed, 29 September 2010 01:46
		Re: why does in_array return true By: Geoff Berrow on Wed, 29 September 2010 10:23

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