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Re: option values with php foreach not working [message #171114 is a reply to message #171112] Sat, 25 December 2010 03:25 Go to previous messageGo to previous message
richard is currently offline  richard   
Messages: 213
Registered: June 2013
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Senior Member
On Fri, 24 Dec 2010 19:58:56 -0700, richard wrote:

> When I run this code locally I get, in firefox, a listbox with "adam" as
> the only output. Nothing else. The second array doesn't even show.
>
> In IE, both items show but I get a warning saying "invalid argument -
> foreach".
> The second array shows up after the warning.
>
> What am I missing?
>
> Dear Santa,
>
> Please bring lots of coal! We need the heat!
>
>
>
>
> <select name="menu1" size="10">
> <option value="101">adam</option>
>
> <?php
>
> $myArray="(1,2,3,4,5)";
> foreach ($myArray as $myItem) {
> echo "<option value='$myItem'>$myItem</option>\n"; }
>
> $arr = array("one", "two", "three");
> foreach ($arr as $key => $value) {
> echo "Key: $key; Value: $value<br />\n";
> }
>
>
> ?>
>
>
> </select>

Notice I had the second array where it shouldn't be and moved it out of
that part.

Still I get a warning for an invalid argument foreach.
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