| Re: You will all probably laugh at this. [message #172493 is a reply to message #172492] |
Mon, 21 February 2011 11:15   |
Rob Bradford
Messages: 5
Registered: February 2011
Karma:
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Junior Member |
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On Feb 21, 11:05 am, "Álvaro G. Vicario"
<alvaro.NOSPAMTH...@demogracia.com.invalid> wrote:
> El 21/02/2011 11:58, Rob Bradford escribi /wrote:
>
>
>
>> I can't get a call to an external php scrip to execute, it jst lists
>> the code in the page rather than run it. If I place the code directly
>> into the page it runs fine. As the code is a db connect string I dont
>> want in an external php that is called as an when required.
>
>> Within the base page I have tried:
>
>> <?php
>> include("con.php");
>> other php in-line code
>> ?>
>
>> and
>
>> <?php
>> require("con.php");
>> other php in-line code
>> ?>
>
>> All that happens is it echo's the contents of con.php then the rest
>> fails as there is no db connection. I'm fairly new to this, but not
>> programming. To be honest the google pages I have pulled up have been
>> no help, has anyone any idea what I am doing wrong.
>
> You don't post the contents of "con.php" but I'd dare say you are
> omitting the PHP delimiters: <?php ... ?>
>
> When a file is included, parsing drops out of PHP mode and into HTML
> mode at the beginning of the target file, and resumes again at the end.
> For this reason, any code inside the target file which should be
> executed as PHP code must be enclosed within valid PHP start and end tags..
>
> http://es2.php.net/manual/en/function.include.php
>
> --
> --http://alvaro.es- lvaro G. Vicario - Burgos, Spain
> -- Mi sitio sobre programaci n web:http://borrame.com
> -- Mi web de humor satinado:http://www.demogracia.com
> --
That was it, I knew it had to be something stupid! I was foolish
enough to think that having invoked the <?php code block the include
would be interpreted as php implicitly.
Thanks for helping out while I still have some hair on my head.
Rob.
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