| Re: Pipe the content of a variable to a process [message #173037 is a reply to message #173036] |
Fri, 18 March 2011 14:05   |
Marco
Messages: 11
Registered: March 2011
Karma:
|
Junior Member |
|
|
On 2011-03-18 Jerry Stuckle <jstucklex(at)attglobal(dot)net> wrote:
> I understand that produces the correct output. But from what I read in
> the doc, -e says to use stdin - which is what you're trying to use.
> Without -e it goes to the command line, which you are not doing. So
> it'd doing exactly what you tell it to do - nothing.
That's incorrect. Without »-e« gnuplot reads from stdin, with »-e« from the
command line. You can check this.
gnuplot -e 'set terminal svg;plot sin(x)'
echo 'set terminal svg;plot sin(x)' | gnuplot
give both the same output.
> I suggest you ask the gnuplot people. I don't think the problem is the
> output stream is failing - I think your commands are incorrect.
I know gnuplot pretty well. Without arguments it can be used directly in a
pipe (with proper input on stdin, of course). It would be difficult to get
help in the gnuplot group, since it works on the command line.
Marco
|
|
|
|
Calendar
Search
Help
Members
Register
Login
Home
]