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Re: problem saving date fields [message #174079 is a reply to message #174076] Sat, 21 May 2011 03:13 Go to previous messageGo to previous message
Jeff North is currently offline  Jeff North
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On Fri, 20 May 2011 22:35:03 -0400, in comp.lang.php Jerry Stuckle
<jstucklex(at)attglobal(dot)net>
<ir78cp$53s$1(at)dont-email(dot)me> wrote:

> | On 5/20/2011 6:58 PM, Jeff North wrote:
> | > On Fri, 20 May 2011 11:38:06 -0700 (PDT), in comp.lang.php Co
> | > <vonclausowitz(at)gmail(dot)com>
> | > <2407eb47-b406-432c-9aed-b76abc94aae9(at)z37g2000vbl(dot)googlegroups(dot)com>
> | > wrote:
> | >
> | >> | Hi All,
> | >> |
> | >> | I have two date fields.
> | >> | When I change of them the other one gets set back to default:
> | >> | 00-00-0000
> | >> | I have to save both to make it work. Is there a solution for this?
> | >> |
> | >> | The arrival_date and departure_date are build up like this:

[snip]

> | >> |<select name="arrival_year" class="formFields" id="arrival_year">
> | >> |<option value="<?php print "$arrival_year"; ?>"><?php print
> | >> | "$arrival_year"; ?></option>
> | >> |<option value="2011">2013</option>
> | >> |<option value="2011">2012</option>
> | >> |<option value="2011">2011</option>
> | >> |<option value="2010">2010</option> etc......
> | >
> | > How are you setting the $arrival_* and $depature_* values?
> |
> | From the input - after is is sent from his form.

Therefore the variables aren't initialised and would cause php errors
- right?

> | > If this is a new entry then all of the $arrival_* and $depature_* will
> | > be null or zero - therefore the select options will not be
> | > automatically selected (View Source of the page to see if there are
> | > any error messages within these lists).
> |
> | No, because he isn't setting them until after the form has been
> | displayed and the user has made his selection.

Methinks you are making too many assumptions - have you seen the full
source code of the page?

> | > You might want to initialise the values by:
> | > $arrival_day = $depature_day = date('j');
> | > $arrival_month = $depature_month = date('n');
> | > $arrival_year = $depature_year = date('Y');
> | >
> | > If you read a record from the database then you would over write the
> | > above values. This will ensure that correct values within the select
> | > lists are automatically selected.
> |
> | No, it is NOT a good idea to add a row every time the page is displayed.
> | Wait for the user to respond to the request, then add it to the
> | database, as he is already doing.

Who said anything about "add a row every time the page is displayed".
According to your criteria there would never be any edit pages - only
add pages.

If editing an existing item wouldn't you want to read the already
stored data from the database?

i.e.
// initialise variables to meaningful values
// if editing an existing entry
// read record
// overwrite initialised variables
// display the page

> | >> | The table is updated like this:

[snip]

> | >> | $departure_month = preg_replace('#[^0-9]#i', '',
> | >> | $_POST['departure_month']);
> | >> | $departure_day = preg_replace('#[^0-9]#i', '',
> | >> | $_POST['departure_day']); // filter everything but numbers
> | >> | $departure_year = preg_replace('#[^0-9]#i', '',
> | >> | $_POST['departure_year']); //
> | >> | $departure_date = "$departure_year-$departure_month-$departure_day";
> | >
> | > You are assuming that items within the listboxs have been selected
> | > (normally this the case only if the initial setup is correct).
> | > You should use
> | > $arrival_day = ( isset( $_POST['arrival_day'] ) ?
> | > intval($_POST['arrival_day']) : 0;
> | > if( $arrival_day == 0 ) { $pageError = "Invalid arrival day number";}
> | >
> | > I also assume that you are checking that you can't arrive before you
> | > depart :-)
> |
> | He needs to do other validation on the data also, but first he needs to
> | get this part working.

....and how do you know this, hmmmm?

> | >> | $sqlUpdate = mysql_query("UPDATE myMembers SET
> | >> | firstname='$firstname', lastname='$lastname', gender='$gender',
> | >> | partner='$partner', country='$country', rank='$rank',
> | >> | service='$service', position='$position',
> | >> | arrival_date='$arrival_date',departure_date='$departure_date' WHERE
> | >> | id='$id' LIMIT 1");
> | >> |
> | >> | Is there a reason why this happens? I do create the right format to
> | >> | put the data back in the table.
> | >
> | > But are the values your setting the ones you expect?
> |
> | That's why the suggestion to print the SQL statement he generated.

The SQL statement should be ok - it's the "When I change of them the
other one gets set back to default: 00-00-0000" I'm considering.

> | BTW - your sig separator is broken. It needs to be exactly
> | hyphen-hyphen-space-newline.

Oh Jerry is now the sig line cop :-P
Complain to the writers of Thunderbird as I couldn't care less about
whether or not my sig appears 'correctly' in your news reader.
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