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Re: problem saving date fields [message #174167 is a reply to message #174162] Mon, 23 May 2011 22:00 Go to previous messageGo to previous message
Jerry Stuckle is currently offline  Jerry Stuckle
Messages: 2598
Registered: September 2010
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Senior Member
On 5/23/2011 3:17 PM, Co wrote:
> On 23 mei, 20:16, Jerry Stuckle<jstuck...@attglobal.net> wrote:
>> On 5/23/2011 1:27 PM, Co wrote:
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>> On 23 mei, 13:13, Jerry Stuckle<jstuck...@attglobal.net> wrote:
>>>> On 5/23/2011 12:51 AM, Co wrote:
>>
>>>> >> ==================
>>
>>>> > Wow you guys really love each other.
>>
>>>> > Marco
>>
>>>> Yea, unfortunately, you have to put up with some trolls on usenet.
>>
>>> So when one of the three dates is not changed it returns the month
>>> written.
>>> Than this code:
>>> $arrival_month = preg_replace('#[^0-9]#i', '',
>>> $_POST['arrival_month']);
>>> ruins the date and it gets set back to 00-00-0000.
>>> Is there a way to detect changes? because than I could set an if
>>> statement before
>>> running the UPDATE query and we leave out the dates that were not
>>> changed.
>>
>>> Marco
>>
>> OK, the question is, where is it getting the month name instead of the
>> number? It has to be coming from your html code. Look at the page
>> source and see where you're putting 'April' in there instead of 4.
>>
>> As for detecting when the data changed - the only way is to do something
>> like save the current data in your $_SESSION and compare when it is
>> retrieved. However, that isn't necessary if you get your problem with
>> the month name being retrieved. It doesn't hurt to update a value in
>> the database with the same value.
>>
>> --
>> ==================
>> Remove the "x" from my email address
>> Jerry Stuckle
>> JDS Computer Training Corp.
>> jstuck...@attglobal.net
>> ==================
>
> It is getting the name of the month when the pulldown menu is filled.
>
> <select name="arrival_month" class="formFields" id="arrival_month">
> <option value="<?php print "$arrival_month"; ?>"><?php print
> "$arrival_month"; ?></option>
> <option value="01">January</option>
> <option value="02">February</option>
> <option value="03">March</option>
> <option value="04">April</option>
> <option value="05">May</option>
> <option value="06">June</option>
> <option value="07">July</option>
> <option value="08">August</option>
> <option value="09">September</option>
> <option value="10">October</option>
> <option value="11">November</option>
> <option value="12">December</option>
> </select>
>
> The problem is that during the Post it returns the name instead of the
> number.
>
> I tried this code but when I don't change the month it doesn't pass
> the code:
> if(!is_numeric($arrival_month)) {
>
> for($i=1;$i<=12;$i++){
> if(strtolower(date("M", mktime(0, 0, 0, $i, 1, 0))) ==
> strtolower($arrival_month)){
> $arrival_month = $i;
> }
> }
> print $arrival_month;
> }
>
> Marco

Of course it will. You have:

<option value="<?php print "$arrival_month"; ?>"><?php print
"$arrival_month"; ?></option>

Which has the month name as its option value. If the arrival month were
April, you would have two Aprils - the first one in the SELECT element
with a value of 'April', then one later with a value of '4'.

You need to straighten out your HTML. You only need one APRIL. Look
up the SELECT/OPTION element and learn how to display the previously
selected value instead of the first value (hint: look for the SELECTED
keyword).

--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex(at)attglobal(dot)net
==================

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