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Re: ArrayObject - copy or reference [message #175161 is a reply to message #175150]

Thu, 18 August 2011 11:48

Thomas Mlynarczyk
Messages: 131
Registered: September 2010

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Senior Member

Jo Schulze schrieb:

>> $array = array( 1, 2, 3 );
>> $obj = new ArrayObject( $array );
>> $obj[0] = 42;
>> echo $array[0];
>>
>> With PHP 5.2.0 this prints 42, with PHP 5.2.4 however, I get 1

> With PHP5.3.7rc this prints 42 which I would expect.

No it doesn't. I just installed PHP 5.3.7RC5 to test it. It prints 1.

> The line
> $obj[0] = 42;
> overwites the value with hash key 0

It overwrites the value with hash key 0 in *$obj*. But it should not
modify *$array*.

> I see no bug here.

There has definitely been a change in behaviour somewhere between 5.2.0
and 5.2.4. And that should be documented somewhere.

Greetings,
Thomas

--
Ce n'est pas parce qu'ils sont nombreux à avoir tort qu'ils ont raison!
(Coluche)

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[Message index]

		ArrayObject - copy or reference By: Thomas Mlynarczyk on Mon, 08 August 2011 17:28
		Re: ArrayObject - copy or reference By: Jo Schulze on Tue, 16 August 2011 22:03
		Re: ArrayObject - copy or reference By: Thomas Mlynarczyk on Thu, 18 August 2011 11:48
		Re: ArrayObject - copy or reference By: Jerry Stuckle on Thu, 18 August 2011 17:54
		Re: ArrayObject - copy or reference By: Thomas Mlynarczyk on Thu, 18 August 2011 18:44
		Re: ArrayObject - copy or reference By: Jerry Stuckle on Thu, 18 August 2011 23:26

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