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Problem with Populating Persian(Arabic) Number in PHP
| Re: Problem with Populating Persian(Arabic) Number in PHP [message #175854 is a reply to message #175853] |
Mon, 31 October 2011 08:30  |
alvaro.NOSPAMTHANX
Messages: 277
Registered: September 2010
Karma:
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Senior Member |
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El 31/10/2011 8:25, beh escribió/wrote:
> Can you please let me know why I am getting error on populating
> Persian(Arabic)Numbers?!
> I have saved the php file as "Uncode in UTF-8" format which can
> display the dropdown list in a HTML correctly but when I want to
> retrieve them in PHP I encountered with following errors
> Errors:
> (!) Notice: Use of undefined constant ١ - assumed '١' in C:\wamp\www
> \PHPCode\Test.php on line 14
> (!) Notice: Use of undefined constant ٣١ - assumed '٣١' in C:\wamp\www
> \PHPCode\Test.php on line 14
> * ١ = is a Persian number equal to 1
> * ٣١ = is a Persian number equal to 31
> Code:
>
> <?php
> $numberArray = array();
>
> for ($i = ١; $i< ٣١; $i++)
> {
> $numberArray[] = $i;
> }
> for ($i = 0; $i< sizeof($numberArray); $i++) {
> echo "$numberArray[$i]"."<br />";
> }
> ?>
>
> I really appreciate your time regarding this.
PHP (as most other computer languages out there) expects English
numbers, period. You can perform calculations with other type of numbers
more than you can translate "while()" or "for()" into other languages.
You can't even use comma as decimal separator. It's simply how the
syntax language has been defined.
--
-- http://alvaro.es - Álvaro G. Vicario - Burgos, Spain
-- Mi sitio sobre programación web: http://borrame.com
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