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Re: Beginner's trouble with substr [message #179455 is a reply to message #179454] Mon, 29 October 2012 17:34 Go to previous messageGo to previous message
Salvatore is currently offline  Salvatore
Messages: 38
Registered: September 2012
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On 2012-10-29, wrong(dot)address(dot)1(at)gmail(dot)com <wrong(dot)address(dot)1(at)gmail(dot)com> wrote:
>
> What am I doing wrong in this? The substr part does not seem to get processed properly.
>
> <?php
>
> global $host;
> $host=@gethostbyaddr($REMOTE_ADDR);
> if ($HTTP_SERVER_VARS["HTTP_X_FORWARDED_FOR"] != "")
> {$realhost = @gethostbyaddr($HTTP_SERVER_VARS["HTTP_X_FORWARDED_FOR"]);}
> $referer = $HTTP_REFERER;
>
> if (substr($host, -3) == ".xy") {exit;} //
> if (substr($host, 6) == "abcd29") {exit;} //
> if (substr($referer, -4) == ".xyz") {exit;} //
>
> if ($found == 1) {include 'simple.html';} else {include 'home.html';}
>
> ?>

The first thing I see wrong is that the variable "$found" is not
declared.

What are you trying to achieve?

--
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