Re: change of color on a field value basis in a table... [message #180748 is a reply to message #180743] |
Sat, 16 March 2013 16:17 |
Nagaraju Kachapuram
Messages: 14 Registered: February 2013
Karma:
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Junior Member |
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On Saturday, 16 March 2013 18:46:53 UTC+5:30, nag wrote:
> Hi,
>
> I am a newbie to php. Here I am trying to print the table rows with different colors based on a value of a field. But it is displaying the very first record in different color and next is the other color until the date field changes.
>
>
>
> suppose:
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>
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> id dt
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> xyz 05 (this is in #a99999 color)
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> abc 05 (this is in #ffffff color)
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> 123 05 (this is in #ffffff color)
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> 324 06 (this is in #a99999 color)
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> ccc 06 (this is in #ffffff color)
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>
>
>
>
> but i need first three (with 05 date) in same color and next records in other color alternatively.
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> the following is my code:
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>
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> if($tmp!=$dt){$color="#a99999"; $tmp=$dt;}else{$color="#ffffff";}
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>
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> while($row = mysql_fetch_array( $result )) {
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> $id=$row[1];
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>
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> $dt=substr($row[5],5,2);
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>
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> // Print out the contents of each row into a table
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>
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> $slno++;
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> $tmp=$dt;
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> if($tmp!=$dt){$color="#a99999"; $tmp=$dt;}else{$color="#ffffff";}
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>
>
> echo "<tr bgcolor='$color'><td align='right'>";
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> echo $slno;
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> echo "</td><td><b>";
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> echo $row[0];
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> echo "</td><td align='center'>";
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> ?>
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> <a href="profile.php?id=<?php echo $idnum; ?>"><?php echo $idnum;?>
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> </a>
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> <?PHP
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> echo "</td><td>";
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> echo sprintf("%07d",$row[2]);
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> echo "</td><td align='center'>";
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> echo $row[3];
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> echo "</td><td align='center'><b>";
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> echo $row[4];
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> echo "</td><td align='center'>";
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> echo $row[5];
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> echo "</td><tr>";
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> }
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> echo "</table>";
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>
>
> thank you.
Here in my data the date differs in a month. So I want to display same month records in one color. Maximum i will have three different months records. Thats the reason i am checking $dt (month tag from the date) is same from the previous date.
the code :
if($tmp!=$dt){
$color="#a99999";
$tmp=$dt;
}else{
$color="#ffffff";
}
is not working.
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