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Re: CTYPE THREAD RESOLVED [message #182685 is a reply to message #182680] Tue, 27 August 2013 21:18 Go to previous message
bill is currently offline  bill
Messages: 310
Registered: October 2010
Karma:
Senior Member
On 2013-08-26 2:07 PM, Fiver wrote:
> On 2013-08-25 21:35, Twayne wrote:
>> If anyone is interested, here's the code I ended up with. It still
>> needs to validate alphabetic & numeric array positions but that should
>> be reasonably simple to add by checking the array positions for alpha or
>> digit characters.
>>
>> Thanks for all the help!
>> -----------------------------------
>> $zip = check_input($zip);
>> $zip = strtoupper($zip);
>> // DETERMINE IF US POSTAL CODE
>> if(strlen($zip)===5) {
>> echo "U.S. postal code used "; }
>> IF (is_numeric($zip)) {
>> echo " and is 5 digits.";
>> }
>> IF(strlen($zip) === 7) {
>> echo "Zip appears to be Canadian . <br />";
>> }
>> // ================== NOW LOOK TO SEE IF IT'S ALPHA-NUMERIC
>>
>> // ================ LET'S ASSIGN IT TO AN ARRAY
>> echo ' <pre>';
>> print_r(str_split($zip,1));
>> echo '</pre>';
>>
>> // ================= check space is where it belongs
>> if($zip[3] === " ") {
>> echo "<br />Space in correct place<br />";
>> }
>>
>> $sUser = $zip;
>> $aValid = array(' ');
>> if(!ctype_alnum(str_replace($aValid, '', $sUser))) {
>> echo "Username has a problem";
>> echo 'Your Postal Code is NOT properly formatted.';
>> }
>> else {
>> echo "Postal code is properly formatted as ALPHA NUMERIC with ONE SPACE
>> as the 4th character";
>> }
>
> For the US zip codes:
>
> is_numeric() is not the correct function to use here. "+.1e1" and
> "0xCAB" are both numeric strings and would pass as US zip codes.

OOPS! Good catch!

> Better solution:
>
> if (strlen($zip) == 5 && ctype_digit($zip)) {
> echo "looks like a US zip code\n";
> }
>
> Better yet: check for known bad zip codes as well

Good point.

>
> ... && $zip != "00000" && $zip != "99999" && I don't know, some more
>
> For the Canadian zip codes:
>
> Your code has a comment "let's assign it to an array", and you also
> wrote that you still needed to validate the array positions, but you
> never do create an array (except for the unnecessary one in $aValid,
> which should probably be a string).

Agreed; the original array code was removed at that point in the coding.

>
> Anyway, you're right that you still need to check the characters to the
> right and left of the space, or strings like "x " and " 3 "
> would be seen as valid zip codes. Here's one way to do it:
>
> if (strlen($zip) == 7
> && $zip[3] == " "
> && ctype_alpha($zip[0] . $zip[2] . $zip[5])
> && ctype_digit($zip[1] . $zip[4] . $zip[6]))
> {
> echo "looks like a Canadian zip code\n";
> }
>
> Note the two closing parens after $zip[6] ;)
>
>
> regards,
> 5er
....

Hmm, ALL great observations; thanks much.
I'll have a look at everything you mentioned here. It's much more
efficient than I've been putting together so far.

Regards,

Twayne`

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