| Re: signed int64 pack/unpack [message #184621 is a reply to message #184612] |
Mon, 13 January 2014 01:59   |
Ben Bacarisse
Messages: 82
Registered: November 2013
Karma:
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Member |
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Jerry Stuckle <jstucklex(at)attglobal(dot)net> writes:
> On 1/12/2014 5:35 PM, Ben Bacarisse wrote:
>> Jerry Stuckle <jstucklex(at)attglobal(dot)net> writes:
>> <snip>
>>> Yes, I know. But he keeps referring to information that is > 15 years
>>> old. PHP has changed a lot since then, but we just wants to argue.
>>
>> Old information can be accurate. I don't know if it is in this case,
>> but it explains the OP's results better than the more recent PHP
>> documentation does. When I asked you your opinion of what's happening,
>> you went all angry and weird.
>>
>
> Exactly. You don't know if the information is accurate. Yet you
> continue to argue about it.
>
> And more recent PHP documentation is more accurate because it relates
> to the CURRENT code base, not one that is over 15 years old.
I could not find an explanation in the PHP documentation. I am sure it
is more up-to-date (and more applicable) but there was no answer there
that I could see.
As it happens, the current code base references Perl for the behaviour.
A comment at the start of pack.c says:
/* pack() idea stolen from Perl (implemented formats behave the same as there)
* Implemented formats are Z, A, a, h, H, c, C, s, S, i, I, l, L, n, N, f, d, x, X, @.
*/
So the code authors would have pointed me to Perl's pack function had I
not already gone there and, as documented, the code for the i and I are
based on the size of a C int (on the build system):
case 'i':
case 'I':
while (arg-- > 0) {
php_pack(argv[currentarg++], sizeof(int), int_map, &output[outputpos]);
outputpos += sizeof(int);
}
break;
> As for getting "angry and weird" - maybe I'm just tired of arguing
> with people who base their position on old and/or inaccurate
> information (or translation thereof), and refuse to look at any other
> possibility.
I am open to other possibilities. What is your opinion about what i and
I do and the size of integer they work with?. I didn't pretend to know
what is actually going on, just what seemed to be going on.
--
Ben.
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