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Re: Problems modifying date using regex [message #169974 is a reply to message #169968]

Sat, 02 October 2010 14:11

Rob
Messages: 5
Registered: October 2010

Karma:

Junior Member

<?php

function _format_date ($op, $days) {
echo $op . $days . ' day';
echo '<br />';
$str = "$op$days day";
echo $str;
echo '<br />';
return ($str);
// $date = new DateTime ();
// $date -> modify ($op . $days . ' day');
// return ($date -> format ('Y-m-d'));
}

$letter = 'Please respond by {{DATE+10}}.';

$letter_subs = array (
'/\{\{DATE([+\-])(\d{1,3})\}\}/i' => _format_date ('\1', '\2'),
);

$parsed_letter = preg_replace (array_keys ($letter_subs), array_values
($letter_subs), $letter);

echo $parsed_letter;

?>

The above (assuming it came through unmolested) returns:

\1\2 day
\1\2 day
Please respond by +10 day.

Because I pulled this out of a larger application that's echoing the
parsed letter, I always tested using return rather than echo. Seeing
the \1\2 being echoed now leads me to assume that what's being passed
to the aren't actual backreference results, but instead the literal
\1\2 strings, which explains 1) why date->modify fails, and 2) why I
saw it as returning the correct information.

So, I guess my question changes from why isn't the date conversion
working to "How can I get the actual backreference results passed to a
function?"

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[Message index]

		Problems modifying date using regex By: Rob on Sat, 02 October 2010 02:23
		Re: Problems modifying date using regex By: Jerry Stuckle on Sat, 02 October 2010 03:08
		Re: Problems modifying date using regex By: Rob on Sat, 02 October 2010 03:24
		Re: Problems modifying date using regex By: Captain Paralytic on Sat, 02 October 2010 09:20
		Re: Problems modifying date using regex By: Rob on Sat, 02 October 2010 14:11
		Re: Problems modifying date using regex By: Rob on Sat, 02 October 2010 15:43

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