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Re: ArrayObject - copy or reference [message #175171 is a reply to message #175161]

Thu, 18 August 2011 17:54

Jerry Stuckle
Messages: 2598
Registered: September 2010

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Senior Member

On 8/18/2011 7:48 AM, Thomas Mlynarczyk wrote:
> Jo Schulze schrieb:
>
>>> $array = array( 1, 2, 3 );
>>> $obj = new ArrayObject( $array );
>>> $obj[0] = 42;
>>> echo $array[0];
>>>
>>> With PHP 5.2.0 this prints 42, with PHP 5.2.4 however, I get 1
>
>> With PHP5.3.7rc this prints 42 which I would expect.
>
> No it doesn't. I just installed PHP 5.3.7RC5 to test it. It prints 1.
>
>> The line
>> $obj[0] = 42;
>> overwites the value with hash key 0
>
> It overwrites the value with hash key 0 in *$obj*. But it should not
> modify *$array*.
>
>> I see no bug here.
>
> There has definitely been a change in behaviour somewhere between 5.2.0
> and 5.2.4. And that should be documented somewhere.
>
> Greetings,
> Thomas
>

Thomas,

I get 1 here also (php 5.2.4). I would consider this a bug - you might
want to post it to bugs.php.net.

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JDS Computer Training Corp.
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[Message index]

		ArrayObject - copy or reference By: Thomas Mlynarczyk on Mon, 08 August 2011 17:28
		Re: ArrayObject - copy or reference By: Jo Schulze on Tue, 16 August 2011 22:03
		Re: ArrayObject - copy or reference By: Thomas Mlynarczyk on Thu, 18 August 2011 11:48
		Re: ArrayObject - copy or reference By: Jerry Stuckle on Thu, 18 August 2011 17:54
		Re: ArrayObject - copy or reference By: Thomas Mlynarczyk on Thu, 18 August 2011 18:44
		Re: ArrayObject - copy or reference By: Jerry Stuckle on Thu, 18 August 2011 23:26

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