| Re: Implied cast differs from explicit cast [message #176687 is a reply to message #176682] |
Tue, 17 January 2012 13:17   |
Jerry Stuckle
Messages: 2598
Registered: September 2010
Karma:
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Senior Member |
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On 1/17/2012 1:00 AM, Arno Welzel wrote:
> Arno Welzel, 2012-01-17 06:59:
>
>> Jerry Stuckle, 2012-01-16 14:45:
>>
>>> On 1/16/2012 8:28 AM, The Natural Philosopher wrote:
>>>> lb wrote:
>>>> > jstucklex(at)attglobal(dot)net wrote:
>>>> >> ...
>>>> >> No, it is not. '0x12' is a hex number, not an integer. (int)'0x12'
>>>> >> converts this correctly to 0.
>>>>
>>>> Looks like Jerry doesn't know what an integer is either.
>>>>
>>>> A hex number of course *is* an integer, unless its a hex representation
>>>> of floating point.
>>>>
>>>> Killfile the prat like I have.
>>>>
>>>>
>>>
>>> 0x12 is not an integer. It is a hexadecimal value.
>>
>> No, 0x12 (and *not* "0x12") is the hexadecimal *representation* of the
>> value 18. There is no thing like "hexadecimal value" and "0x12" is a
>> *string* and not a number at all.
>>
>> In fact PHP only knows to types of numbers: integers and floating point.
>> There is no "hexadecimal" data type.
>>
>>> It can have the same bit pattern as an integer - but it can also have
>>> the same bit pattern as a character (Ctrl-R, to be exact).
>>
>> Which also applies to the value 18 - this can also be the value of a
>> character.
>>
>> Example:
>>
>> <?php
>> $a = 0x12;
>>
>> print $a;
>> ?>
>>
>> Result:
>>
>> Value of $a: 18, type of $a: integer
>
> Sorry - the example was not complete:
>
> <?php
> $a = 0x12;
>
> $a = intval($a, 16);
>
> print 'Value of $a: ' . $a . ', type of $a: ' . gettype($a);
> ?>
>
>
>
Sure. You explicitly converted the hexadecimal value to an integer.
What do you expect?
--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex(at)attglobal(dot)net
==================
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