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Re: Requesting Help with a Regular Expression [message #179443 is a reply to message #179442]

Sun, 28 October 2012 23:39

Denis McMahon
Messages: 634
Registered: September 2010

Karma:

Senior Member

On Sun, 28 Oct 2012 16:08:20 -0700, bobgatski wrote:

> From strings such as these ...
> int(11)
> varchar(45)
> datetime ... I am trying to extract just the type and length; i.e. for
> the type I want ...
> int varchar datetime ... and for the length I want ...
> 11 45 NULL I can get the type using ...
> (\w+)
> ... but I haven't been able to get the type and length. What I think
> should work is ... (\w+)($(\d+)$)?
> ... gets no matches at all,not even the type.

Try:

preg_match( "/(\w+)\(?(\d+)?/", $target, $arr );

<?php

$arr = array();
$arr[] = "int(11)";
$arr[] = "varchar(45)";
$arr[] = "datetime";

foreach ( $arr as $x ) {
if ( preg_match( "/(\w+)\(?(\d+)?/", $x, $arr2 ) == 1 ) {
echo "\$x = \"{$x}\"";
echo ", \$arr2[0] = \"{$arr2[0]}\"";
echo ", \$arr2[1] = \"{$arr2[1]}\"";
if ( isset( $arr2[2] ) )
echo ", \$arr2[2] = \"{$arr2[2]}\"";
echo "\n";
}
else {
echo "\$x = \"{$x}\" - No match or regex error!\n";
}
}

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[Message index]

		Requesting Help with a Regular Expression By: bobgatski on Sun, 28 October 2012 23:08
		Re: Requesting Help with a Regular Expression By: Denis McMahon on Sun, 28 October 2012 23:39
		Re: Requesting Help with a Regular Expression By: bobgatski on Mon, 29 October 2012 14:34

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