| Re: solved! Re: Filling an array with random input doesn't quite work [message #185257 is a reply to message #185219] |
Fri, 14 March 2014 22:23   |
Thomas 'PointedEars'
Messages: 701
Registered: October 2010
Karma:
|
Senior Member |
|
|
Christoph Michael Becker wrote:
> Tim Streater wrote:
>> richard <noreply(at)example(dot)com> wrote:
>>> $x=1;
>>> while ($x<40){
>>> $yr=rand(1,10);
>>> $yr=$yr+59;
>>> $num=rand(1,100);
>>> if ($num<100){$num="0".$num;}
>>> if ($num<10){$num="0".$num;}
>>
>> What is the point if this second "if"? You've already covered that with
>> the first.
>
> That serves to add padding to three characters. The last three lines
> could be replaced with the following:
>
> str_pad(rand(1, 100), 3, '0', STR_PAD_LEFT);
$num = str_pad(rand(1, 100), 3, '0', STR_PAD_LEFT);
as str_pad() does not modify strings (because they are immutable).
Or simply
$num = sprintf('%03d', rand(1, 100));
:)
PointedEars
--
Prototype.js was written by people who don't know javascript for people
who don't know javascript. People who don't know javascript are not
the best source of advice on designing systems that use javascript.
-- Richard Cornford, cljs, <f806at$ail$1$8300dec7(at)news(dot)demon(dot)co(dot)uk>
|
|
|
|
Calendar
Search
Help
Members
Register
Login
Home
]