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Re: count() problem [message #185707 is a reply to message #185705] Sat, 03 May 2014 18:33 Go to previous messageGo to previous message
Richard Yates is currently offline  Richard Yates
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Registered: September 2013
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On Sat, 3 May 2014 14:18:22 -0400, richard <noreply(at)example(dot)com>
wrote:

>
> $dir = '../audio/'.$yr.'/';
> $files = scandir($dir);
> $number=count(files);
> echo $number;
>
> Why does this always show the resutlt as 1?

Because you left out a '$'
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