| why can`t close mysql_connect? [message #179631] |
Thu, 15 November 2012 10:19  |
cngrit0305
Messages: 4
Registered: November 2012
Karma:
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Junior Member |
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hi,
I am a novice with php,today,I found can`t close mysql_connect.
I have a object "db_config.php"
class DbConfig{
private $db_url = 'localhost:3333';
private $db_user = 'root';
private $db_pwd = 'root';
private $db_name = 'xinxiwang';
function __get($property_name){
return $this->$property_name;
}
public function getConn(){
$link = mysql_connect($this->db_url,$this->db_user,$this->db_pwd)
or die("can not connect to Mysql server");
mysql_select_db($this->db_name,$link)
or die("can not found database " . $this->db_name );
return $link;
}
}
I will in a other php file include it "test.php"
require (db_config.php);
function fri_select($db,$pagenum,$counts){
$sql = "call friendlink_select($pagenum,$counts)";
$result = mysql_query($sql,$db);
mysql_close($db);
if($db){
echo "in function, con is alive;<br>";
}else{
echo "in function , con is dead";
}
if(isset($db)){
echo "in function,con is alive;<br>";
}else{
echo "in function , con is dead";
}
if(!empty($db)){
echo "in function,con is alive;<br>";
}else{
echo "in function , con is dead";
}
return $result;
}
$db = new DbConfig();
$dbs = $db->getConn();
$result = fri_select($dbs,1,6);
if($dbs){
echo "out function, con is alive;<br>";
}else{
echo "out function , con is dead";
}
if(isset($dbs)){
echo "out function,con is alive;<br>";
}else{
echo "out function , con is dead";
}
if(!empty($dbs)){
echo "out function,con is alive;<br>";
}else{
echo "out function , con is dead";
}
it will out put
in function,con is alive;
in function,con is alive;
in function,con is alive;
out function, con is alive;
out function,con is alive;
out function,con is alive;
why???I had close it in function!!!who can tell me??
thanks very much!!!
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